If it's not what You are looking for type in the equation solver your own equation and let us solve it.
b^2-16b+28=0
a = 1; b = -16; c = +28;
Δ = b2-4ac
Δ = -162-4·1·28
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-12}{2*1}=\frac{4}{2} =2 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+12}{2*1}=\frac{28}{2} =14 $
| x^2-5+3=0 | | x+(x+2)+(x+4)=-87 | | 6x-(9x+3)=7x-23 | | 4(2x+4)+2=10x+15-2x+1 | | 9-(-x+8)=3-6 | | (7r+5)/2=13 | | (x-2)+x+(x+2)=-87 | | 140.625x=19 | | x+(x+1)+(x+2)=-87 | | 84+7b=9b+66 | | 3x-6=186 | | 140.625=19x | | 3/8x=2/1/2 | | x+7=28•3 | | 5−3(x+9)=9−4 | | 2-v=5(v-4) | | 5x-5+2x=180 | | 2(x^2+7)=4 | | 5−3(x+9)=9−45-3(x+9)=9-4 | | 6x+18x-4=5(5x+4) | | 25=27-2(5-1w) | | 1444x=76 | | 1444=76x | | 3200000-y=4y | | 2(4y-3)+2=24 | | -3(x+11)+335=26+12 | | 1/9x=-108 | | 7x^2+168=77x | | 1444=19x | | 1444x=38 | | 1444=38x | | 8k-(-3+2k)=6 |